Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Section 2.3 - Solving Linear Equations - Exercise Set - Page 141: 30

Answer

z=-10

Work Step by Step

-2(z-4)-(3z-2)=-2-(6z-2) -2(z)-2(-4)-(3z)-(-2)=-2-(6z)-(-2) -2z+8-3z+2=-2-6z+2 (-2z-3z)+(8+2)=-6z+(-2+2) -5z+10=-6z+0 -5z+6z+10=0 z+10=0 z=-10 Check the answer. -2(-10-4)-(3(-10)-2)=-2-(6(-10)-2) -2(-14)-(-30-2)=-2-(-60-2) 28-(-32)=-2-(-62) 28+32=-2+62 60=60
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