Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Section 2.3 - Solving Linear Equations - Exercise Set: 13

Answer

$z=6$

Work Step by Step

$2(4z+3)-8=46$ $2(4z+3)=46+8$ $2(4z+3)=54$ $8z+6=54$ $8z=48$ $8z\div8=48\div8$ $z=6$ Check the answer. 2(4(6)+3)-8=46 2(24+3)-8=46 2(27)-8=46 54-8=46 46=46
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