Answer
$C-A$
Work Step by Step
RECALL:
(1) $\log_b{(\frac{m}{n})} = \log_b{m} - \log_b{n}$
(2) $\log_b{mn} = \log_b{m} + \log_b{n}$
Use rule (1) above to obtain:
$=\log_b{3} - \log_b{2}$
With $\log_b{2} = A$ and $\log_b{3}=C$, the expression above is equivalent to:
$=C-A$
