Answer
$\ln{\frac{x^2}{y^{\frac{1}{2}}}}$
Work Step by Step
The product rule for logarithms says that $log_b{MN}=log_bM+log_bN$ i.e. the logarithm of a product is the sum of the logarithms.
The quotient rule for logarithms says that $log_b{\frac{M}{N}}=log_bM-log_bN$ i.e. the logarithm of a quotient is the difference of the logarithms.
The power rule for logarithms says that $\log_b{M^p}=p\log_bM$ i.e. the logarithm of a number with an exponent is the exponent times the logarithm of the number.
$\log_ba=\frac{\log_ca}{\log_cb}$
Hence here: $2\ln x-\frac{1}{2}\ln y=\ln{x^2}-\ln{y^{\frac{1}{2}}}=\ln{\frac{x^2}{y^{\frac{1}{2}}}}$
