Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.6 - Radical Equations - Exercise Set - Page 562: 87

Answer

$=(y-3+5x)(y-3-5x)$.

Work Step by Step

The given expression is $=y^2-6y+9-25x^2$ Factor each term. $=y^2-2(y)(3)+3^2-(5x)^2$ Group the terms as a perfect square trinomial and perfect square term. $=[y^2-2(y)(3)+3^2]-[(5x)^2]$ Use the special formula $A^2-2AB+B^2=(A-B)^2$. We have $A=y$ and $B=3$ $=(y-3)^2-(5x)^2$ Use the special formula $A^2-B^2=(A+B)(A-B)$. We have $A=y-3$ and $B=5x$ $=(y-3+5x)(y-3-5x)$.
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