Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.6 - Radical Equations - Exercise Set - Page 562: 83

Answer

$\{16\}$.

Work Step by Step

The given equation is $\Rightarrow \sqrt {\sqrt x+\sqrt{x+9}}=3$ Square both sides. $\Rightarrow \left (\sqrt {\sqrt x+\sqrt{x+9}}\right )^2=(3)^2$ Simplify. $\Rightarrow \sqrt x+\sqrt{x+9}=9$ Subtract $\sqrt{x+9}$ from both sides. $\Rightarrow \sqrt x+\sqrt{x+9}-\sqrt{x+9}=9-\sqrt{x+9}$ Simplify. $\Rightarrow \sqrt x=9-\sqrt{x+9}$ Square both sides. $\Rightarrow (\sqrt x)^2=(9-\sqrt{x+9})^2$ Use the special formula $(A+B)^2=A^2+2AB+B^2$ We have $A=9$ and $B=\sqrt{x+9}$ $\Rightarrow x=(9)^2-2(9)( \sqrt{x+9})+(\sqrt{x+9})^2$ Simplify. $\Rightarrow x=81-18 \sqrt{x+9}+x+9$ Add $18 \sqrt{x+9} -x$ to both sides. $\Rightarrow x+18 \sqrt{x+9} -x=81-18 \sqrt{x+9}+x+9+18 \sqrt{x+9} -x$ Simplify. $\Rightarrow 18 \sqrt{x+9} =90$ Divide both sides by $18$. $\Rightarrow \frac{18 \sqrt{x+9}}{18} =\frac{90}{18}$ Simplify. $\Rightarrow \sqrt{x+9} =5$ Square both sides. $\Rightarrow (\sqrt{x+9})^2 =(5)^2$ Simplify. $\Rightarrow x+9 =25$ Subtract $9$ from both sides. $\Rightarrow x+9-9 =25-9$ Simplify. $\Rightarrow x =16$ The solution is $x=\{16\}$.
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