Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.6 - Radical Equations - Exercise Set - Page 562: 82

Answer

$x=81$.

Work Step by Step

The given expression is $\Rightarrow \sqrt[3] {x\sqrt x}=9$ We can write as $\Rightarrow [x^1x^{\frac{1}{2}}]^{\frac{1}{3}}=9$ $\Rightarrow [x^{1+\frac{1}{2}}]^{\frac{1}{3}}=9$ Simplify. $\Rightarrow [x^{\frac{3}{2}}]^{\frac{1}{3}}=9$ Use the power rule. $\Rightarrow x^{\frac{3}{2}\cdot \frac{1}{3} }=9$ Simplify. $\Rightarrow x^{ \frac{1}{2} }=9$ Square both sides. $\Rightarrow (x^{ \frac{1}{2} })^{2}=(9)^2$ Use the power rule and simplify. $\Rightarrow x=81$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.