Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 9 - Conic Sections, Sequences, and Series - 9.3 Arithmetic Sequences - 9.3 Exercises - Page 728: 48

Answer

The sequence is arithmetic. Common difference: $d=3.5$. General term: $a_{n}=3.5n-8.5$

Work Step by Step

$-1.5-(-5)=2-(-1.5)=5.5-2=9-5.5=12.5-9=3.5$ We see that the difference between each term and the preceding term is same and is equal to $3.5$. Therefore, the sequence is arithmetic with common difference $d=3.5$. The general term $a_{n}$ is given by $a_{n}=a_{1}+(n-1)d$ As $a_1=-5$ and $d=3.5$, we have: $a_{n}=-5+(n-1)3.5=-5+3.5n-3.5$ $a_{n}=3.5n-8.5$
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