Answer
The sequence is arithmetic.
Common difference: $d=6$.
General term: $a_{n}=6n-2$.
Work Step by Step
$10-4=16-10=22-16=28-22=34-28=6$
We see that the difference between each term and the preceding term is same and is equal to $6$. Therefore, the sequence is arithmetic with common difference $d=6$.
The general term $a_{n}$ is given by
$a_{n}=a_{1}+(n-1)d$
As $a_1=4$ and $d=6$, the general term is:
$a_{n}=4+(n-1)6=4+6n-6$
$a_{n}=6n-2$
