Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 9 - Conic Sections, Sequences, and Series - 9.3 Arithmetic Sequences - 9.3 Exercises: 10

Answer

$\frac{3}{14},\frac{6}{13},\frac{3}{4},\frac{12}{11},\frac{3}{2}$

Work Step by Step

$a_n=\frac{-3n}{n-15}$ $a_1=\frac{-3}{-14}=\frac{3}{14}$ $a_2=\frac{-3\times2}{2-15}=\frac{-6}{-13}=\frac{6}{13}$ $a_3=\frac{-3\times3}{3-15}=\frac{-9}{-12}=\frac{3}{4}$ $a_4=\frac{-3\times4}{4-15}=\frac{-12}{-11}=\frac{12}{11}$ $a_5=\frac{-3\times5}{5-15}=\frac{-15}{-10}=\frac{3}{2}$
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