Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 9 - Conic Sections, Sequences, and Series - 9.3 Arithmetic Sequences - 9.3 Exercises - Page 727: 11

Answer

$\frac{1}{4},\frac{1}{16},\frac{1}{64},\frac{1}{256},\frac{1}{1024}$

Work Step by Step

$a_n=\frac{1}{4^n}$ $a_1=\frac{1}{4^1}=\frac{1}{4}$ $a_2=\frac{1}{4^2}=\frac{1}{16}$ $a_3=\frac{1}{4^3}=\frac{1}{64}$ $a_4=\frac{1}{4^4}=\frac{1}{256}$ $a_5=\frac{1}{4^5}=\frac{1}{1024}$
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