Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 7 - Rational Functions - 7.3 Multiplying and Dividing Rational Expressions - 7.3 Exercises: 45

Answer

$= \frac{6h(h-3)}{(h+4)(h+8)}$

Work Step by Step

$\frac{h^{2}-7h+12}{h^{2}+2h-8} \div \frac{h^{2}+4h-32}{6h^{2}-12h}$ $= \frac{h^{2}-7h+12}{h^{2}+2h-8} \times \frac{6h^{2}-12h}{h^{2}+4h-32}$ $= \frac{(h-3)(h-4)}{(h+4)(h-2)} \times \frac{6h(h-2)}{(h+8)(h-4)}$ $= \frac{(h-3)(h-4)}{(h+4)} \times \frac{6h}{(h+8)(h-4)}$ $= \frac{(h-3)}{(h+4)} \times \frac{6h}{(h+8)}$ $= \frac{6h(h-3)}{(h+4)(h+8)}$
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