Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 7 - Rational Functions - 7.3 Multiplying and Dividing Rational Expressions - 7.3 Exercises: 33

Answer

$= \frac{(x+3)}{(x-8)}$

Work Step by Step

$\frac{(x+3)(x+2)}{(x-8)(x-7)} \div \frac{(x+2)(x-5)}{(x-7)(x-5)}$ $= \frac{(x+3)(x+2)}{(x-8)(x-7)} \times \frac{(x-7)(x-5)}{(x+2)(x-5)}$ $= \frac{(x+3)(x+2)}{(x-8)(x-7)} \times \frac{(x-7)}{(x+2)}$ $= \frac{(x+3)(x+2)}{(x-8)} \times \frac{1}{(x+2)}$ $= \frac{(x+3)}{(x-8)} \times \frac{1}{1}$ $= \frac{(x+3)}{(x-8)} \times 1$ $= \frac{(x+3)}{(x-8)}$
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