Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 6 - Logarithmic Functions - Chapter Test: 6

Answer

$x = \frac{\frac{\log 8}{\log 3} + 1}{7}$

Work Step by Step

$8 = 3^{7x-1}$ $\log 8 = \log 3^{7x-1}$ $\log 8 = (7x-1)\log 3$ $\frac{\log 8}{\log 3} = 7x-1$ $7x = \frac{\log 8}{\log 3} + 1$ $x = \frac{\frac{\log 8}{\log 3} + 1}{7}$
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