Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 6 - Logarithmic Functions - Chapter Test - Page 543: 5

Answer

$x = \frac{\log 23 - \log 4}{\log 2}$ $x \approx 2.52$

Work Step by Step

$20 = -3+4(2^{x})$ $20 + 3 = 4(2^{x})$ $23 = 4(2^{x})$ $\frac{23}{4} = 2^{x}$ $\log \frac{23}{4} = \log 2^{x}$ $\log \frac{23}{4} = x\log 2$ $x = \frac{\log \frac{23}{4}}{\log 2}$ $x = \frac{\log 23 - \log 4}{\log 2}$ $x \approx 2.52$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.