Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 6 - Logarithmic Functions - Chapter Test: 18

Answer

$h^{-1}(x) = \log_7 (\frac{x}{2})$

Work Step by Step

$h(x) = 2(7)^{x}$ Let $h(x) = y$ $y = 2(7)^{x}$ Swap the variables $x$ and $y$, then solve for $y$ to find the inverse: $x = 2(7)^{y}$ $\frac{x}{2} = (7)^{y}$ $y = \log_7 (\frac{x}{2})$ $h^{-1}(x) = \log_7 (\frac{x}{2})$
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