## Intermediate Algebra (6th Edition)

$(2,-3)$
We are given the following system of equations. $x+2y=-4$ $3x-y=9$ First, we can solve for x in the first equation by subtracting 2y from both sides. $x=-2y-4$ Next, we can insert this into the second equation and solve for y. $3(-2y-4)-y=9$ Use the distributive property to multiply out the left side. $-6y-12-y=-7y-12=9$ Add 12 to both sides. $-7y=21$ Divide both sides by -7. $y=-3$ Plug this back into the first equation. $x+2(-3)=x-6=-4$ Add 6 to both sides. $x=2$