Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.7 - Common Logarithms, Natural Logarithms, and Change of Base - Exercise Set: 67

Answer

$x=\frac{4}{7}$

Work Step by Step

We are given the equation $6x-3(2-5x)=6$. We can use the distributive property to simplify. $6x-3(2-5x)=6x-3(2)-3(-5x)=6x-6+15x=6$ Combine like terms on the left side. $21x-6=6$ Add 6 to both sides. $21x=12$ Divide both sides by 21. $x=\frac{12}{21}=\frac{4}{7}$
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