Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.7 - Common Logarithms, Natural Logarithms, and Change of Base - Exercise Set: 70

Answer

$x=-\frac{4y}{3}$

Work Step by Step

We are given the equation $4x-8y=10x$. To simplify, subtract 4x from both sides. $6x=-8y$ Divide both sides by 6. $x=-\frac{8y}{6}=-\frac{4y}{3}$
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