## Intermediate Algebra (6th Edition)

$x=\frac{e^{.18}}{4}\approx.2993$
We are given the equation $\ln(4x)=.18$. To solve for x, remember that the base of a natural logarithm is understood to be $e$. Therefore, $\ln(4x)=log_{e}4x=.18$. If $b\gt0$ and $b\ne1$, then $y=log_{b}x$ means $x=b^{y}$ for every $x\gt0$ and every real number $y$. Therefore, $4x=e^{.18}$. Divide both sides by 4. $x=\frac{e^{.18}}{4}\approx.2993$