Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.7 - Common Logarithms, Natural Logarithms, and Change of Base - Exercise Set: 18

Answer

-2

Work Step by Step

A common logarithm is a logarithm to base 10. As shown on page 580, when a common logarithm is written in the form $log (x)$, this is equivalent to the expression $log_{10}x$. Therefore, $log \frac{1}{100}=log_{10}\frac{1}{100}=-2$. We know this, because $10^{-2}=\frac{1}{10^{2}}=\frac{1}{10\times10}=\frac{1}{100}$.
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