# Chapter 9 - Section 9.7 - Common Logarithms, Natural Logarithms, and Change of Base - Exercise Set: 39

$x=\frac{e^{2.3}+4}{3}\approx4.6581$

#### Work Step by Step

We are given the equation $\ln(3x-4)=2.3$. To solve for x, remember that the base of a natural logarithm is understood to be $e$. Therefore, $\ln(3x-4)=log_{e}(3x-4)=2.3$. If $b\gt0$ and $b\ne1$, then $y=log_{b}x$ means $x=b^{y}$ for every $x\gt0$ and every real number $y$. Therefore, $3x-4=e^{2.3}$. Add 4 to both sides. $3x=e^{2.3}+4$ Divide both sides by 3. $x=\frac{e^{2.3}+4}{3}\approx4.6581$

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