Answer
$y=3$
Work Step by Step
Using the concepts of radicals, the solution to the given equation, $
y^3-216=0
,$ is
\begin{array}{l}\require{cancel}
y^3=216
\\\\
y=\sqrt[3]{216}
\\\\
y=\sqrt[3]{(6)^3}
\\\\
y=3
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 8 - Section 8.3 - Solving Equations by Using Quadratic Methods - Exercise Set - Page 504: 86
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