Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Section 8.3 - Solving Equations by Using Quadratic Methods - Exercise Set - Page 504: 90

Answer

Please see the graph.

Work Step by Step

The graph shows that the solutions include -1.732, -1.414, 1.414, and -1.732. $\sqrt 3 = ±1.732$ $\sqrt 2 = ±1.414$ The solutions in the original problem were ±\sqrt 3 and ±\sqrt 2. There are no differences as we have equivalent values.
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