Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Cumulative Review - Page 533: 7a

Answer

$6x^{2}-29x+28$

Work Step by Step

$(2x-7)(3x-4)$ =$2x(3x-4)-7(3x-4)$ =$6x^{2}-2x(4)-7(3x)-7(-4)$ =$6x^{2}-8x-21x+28$ =$6x^{2}-29x+28$
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