Answer
$6x^{2}-29x+28$
Work Step by Step
$(2x-7)(3x-4)$
=$2x(3x-4)-7(3x-4)$
=$6x^{2}-2x(4)-7(3x)-7(-4)$
=$6x^{2}-8x-21x+28$
=$6x^{2}-29x+28$
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