Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Cumulative Review - Page 533: 8a

Answer

$28a^{2}-29a+6$

Work Step by Step

$(4a-3)(7a-2)$ =$4a(7a-2)-3(7a-2)$ =$28a^{2}-8a-21a+6$ =$28a^{2}-29a+6$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.