Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Cumulative Review - Page 533: 13

Answer

$3x(2a-b)^{2}$

Work Step by Step

$12a^{2}x-12abx+3b^{2}x$ =$12a^{2}x-6abx-6abx+3b^{2}x$ =$6ax(2a-b)-3bx(2a-b)$ =$(2a-b)(6ax-3bx)$ =$(6ax-3bx)\times(2a-b)$ =$3x(2a-b)\times(2a-b)$ =$3x(2a-b)(2a-b)$ =$3x(2a-b)^{2}$
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