Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Sections 7.1-7.5 - Integrated Review - Radicals and Rational Exponents - Page 447: 35

Answer

$\dfrac{\sqrt{21}}{3}$

Work Step by Step

Multiplying both the numerator and the denominator by $ \sqrt{3} $, then the rationalized-denominator form of the given expression, $ \sqrt{\dfrac{7}{3}} ,$ is equivalent to \begin{array}{l}\require{cancel} \sqrt{\dfrac{7}{3}\cdot\dfrac{3}{3}} \\\\= \sqrt{\dfrac{21}{(3)^2}} \\\\= \dfrac{\sqrt{21}}{\sqrt{(3)^2}} \\\\= \dfrac{\sqrt{21}}{3} .\end{array}
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