Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Sections 7.1-7.5 - Integrated Review - Radicals and Rational Exponents - Page 447: 20

Answer

$\sqrt[6] 500$

Work Step by Step

$\sqrt 5\times\sqrt[3] 2=5^{\frac{1}{2}}\times2^{\frac{1}{3}}=5^{\frac{3}{6}}\times2^{\frac{2}{6}}=\sqrt[6] (5^{3}2^{2})=\sqrt[6] (125\times4)=\sqrt[6] 500$
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