Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Sections 7.1-7.5 - Integrated Review - Radicals and Rational Exponents: 20

Answer

$\sqrt[6] 500$

Work Step by Step

$\sqrt 5\times\sqrt[3] 2=5^{\frac{1}{2}}\times2^{\frac{1}{3}}=5^{\frac{3}{6}}\times2^{\frac{2}{6}}=\sqrt[6] (5^{3}2^{2})=\sqrt[6] (125\times4)=\sqrt[6] 500$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.