Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Sections 7.1-7.5 - Integrated Review - Radicals and Rational Exponents - Page 447: 32

Answer

$10+2\sqrt{21}$

Work Step by Step

Using $(a+b)^2=a^2+2ab+b^2$ or the square of a binomial, the given expression, $ \left( \sqrt{7}+\sqrt{3} \right)^2 ,$ is equivalent to \begin{array}{l}\require{cancel} (\sqrt{7})^2+2(\sqrt{7})(\sqrt{3})+(\sqrt{3})^2 \\\\= 7+2\sqrt{7(3)}+3 \\\\= 10+2\sqrt{21} .\end{array}
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