Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set - Page 464: 115

Answer

$6-3i\sqrt{3}$

Work Step by Step

Using $i=\sqrt{-1}$ and the properties of radicals, the given expression, $ (8-\sqrt{-3})-(2+\sqrt{-12}) ,$ simplifies to \begin{array}{l}\require{cancel} 8-\sqrt{-3}-2-\sqrt{-12} \\\\= (8-2)+(-\sqrt{-3}-\sqrt{-12}) \\\\= (8-2)+(-\sqrt{-1}\cdot\sqrt{3}-\sqrt{-1}\cdot\sqrt{12}) \\\\= (8-2)+(-i\sqrt{3}-i\cdot\sqrt{12}) \\\\= (8-2)+(-i\sqrt{3}-i\cdot\sqrt{4\cdot3}) \\\\= (8-2)+(-i\sqrt{3}-i\cdot\sqrt{(2)^2\cdot3}) \\\\= (8-2)+(-i\sqrt{3}-i\cdot2\sqrt{3}) \\\\= (8-2)+(-i\sqrt{3}-2i\sqrt{3}) \\\\= 6-3i\sqrt{3} .\end{array}
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