Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set - Page 464: 104

Answer

$1+i$

Work Step by Step

Using $i^2=-1$ and the laws of exponents, the given expression, $ i^8-i^7 ,$ is equivalent to \begin{array}{l}\require{cancel} (i^2)^4-i^6\cdot i \\\\= (i^2)^4-(i^2)^3\cdot i \\\\= (-1)^4-(-1)^3\cdot i \\\\= 1-(-1)\cdot i \\\\= 1+i .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.