Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set - Page 464: 105

Answer

$0$

Work Step by Step

Using $i^2=-1$ and the laws of exponents, the given expression, $ i^6+i^8 ,$ is equivalent to \begin{array}{l}\require{cancel} (i^2)^3+(i^2)^4 \\\\= (-1)^3+(-1)^4 \\\\= -1+1 \\\\= 0 .\end{array}
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