Answer
$0$
Work Step by Step
Using $i^2=-1$ and the laws of exponents, the given expression, $
i^6+i^8
,$ is equivalent to
\begin{array}{l}\require{cancel}
(i^2)^3+(i^2)^4
\\\\=
(-1)^3+(-1)^4
\\\\=
-1+1
\\\\=
0
.\end{array}
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