Answer
$\text{approximately } 2.9 \text{ times}$
Work Step by Step
Substituting $x=5$ in the given function, $
F(x)=0.6\sqrt{49-x^2}
,$ results to
\begin{array}{l}\require{cancel}
F(x)=0.6\sqrt{49-5^2}
\\
F(x)=0.6\sqrt{49-25}
\\
F(x)=0.6\sqrt{24}
\\
F(x)=0.6\sqrt{4\cdot6}
\\
F(x)=0.6\sqrt{2^2\cdot6}
\\
F(x)=0.6(2)\sqrt{6}
\\
F(x)=1.2\sqrt{6}
\\
F(x)\approx2.9
.\end{array}
Hence, the demand per week, $F(x),$ of an older released DVD is $
\text{approximately } 2.9 \text{ times}
.$
