Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.3 - Simplifying Radical Expressions - Exercise Set: 117

Answer

$x^{7}$

Work Step by Step

$\sqrt[5] (x^{35})=x^{7}$ We know this because $(x^{7})^{5}=x^{7\times5}=x^{35}$
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