Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.3 - Simplifying Radical Expressions - Exercise Set: 118

Answer

$y^{8}$

Work Step by Step

$\sqrt[6] (y^{48})=y^{8}$ We know this because $(y^{8})^{6}=y^{8\times6}=y^{48}$
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