Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.3 - Simplifying Radical Expressions - Exercise Set: 8

Answer

$\sqrt (15yx)$

Work Step by Step

The product rule holds that $\sqrt[n] a\times\sqrt[n] b=\sqrt[n] (ab)$ (where $\sqrt[n] a$ and $\sqrt[n] b$ are real numbers). Therefore, $\sqrt 3y\times\sqrt 5x=\sqrt (3y\times5x)=\sqrt (15yx)$
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