Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.3 - Simplifying Radical Expressions - Exercise Set: 3

Answer

2

Work Step by Step

The product rule holds that $\sqrt[n] a\times\sqrt[n] b=\sqrt[n] (ab)$ (where $\sqrt[n] a$ and $\sqrt[n] b$ are real numbers). Therefore, $\sqrt[4] 8\times\sqrt[4] 2=\sqrt[4] (8\times2)=\sqrt [4] 16=2$ We know this because $2^{4}=16$.
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