## Intermediate Algebra (6th Edition)

$\frac{\sqrt[4] (x^{3})}{2}$
The quotient rule holds that $\sqrt[n] (\frac{a}{b})=\frac{\sqrt[n] a}{\sqrt[n] b}$ (where $\sqrt[n] a$ and $\sqrt[n] b$ are real numbers and $\sqrt[n] b$ is nonzero). Therefore, $\sqrt[4] (\frac{x^{3}}{16})=\frac{\sqrt[4] (x^{3})}{\sqrt[4] 16}=\frac{\sqrt[4] (x^{3})}{2}$ We know that $\sqrt[4] 16=2$, because $2^{4}=16$.