Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Test - Page 406: 7

Answer

$\dfrac{3}{x^3}$

Work Step by Step

The given expression, $ \dfrac{5}{4x^3}+\dfrac{7}{4x^3} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{5+7}{4x^3} \\\\= \dfrac{12}{4x^3} \\\\= \dfrac{3}{x^3} .\end{array}
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