Answer
$x^2+2x+4$
Work Step by Step
The given expression, $
\dfrac{x^3-8}{x-2}
,$ simplifies to
\begin{array}{l}\require{cancel}
\dfrac{(x-2)(x^2+2x+4)}{x-2}
\\\\=
\dfrac{(\cancel{x-2})(x^2+2x+4)}{\cancel{x-2}}
\\\\=
x^2+2x+4
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 6 - Test - Page 406: 5
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