Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Test - Page 406: 14

Answer

$\dfrac{3}{2}$

Work Step by Step

The given expression, $ \dfrac{3x}{5}\cdot\left( \dfrac{5}{x}-\dfrac{5}{2x} \right) ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{3x}{5}\cdot\dfrac{5}{x}-\dfrac{3x}{5}\cdot\dfrac{5}{2x} \\\\= \dfrac{3\cancel{x}}{\cancel{5}}\cdot\dfrac{\cancel{5}}{\cancel{x}}-\dfrac{3x}{5}\cdot\dfrac{5}{2x} \\\\= 3-\dfrac{3\cancel{x}}{\cancel{5}}\cdot\dfrac{\cancel{5}}{2\cancel{x}} \\\\= 3-\dfrac{3}{2} \\\\= \dfrac{6}{2}-\dfrac{3}{2} \\\\= \dfrac{3}{2} .\end{array}
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