Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.8 - Solving Equations by Factoring and Problem Solving - Exercise Set: 6

Answer

{4, 6}

Work Step by Step

1. Factor and check by multiplying with FOIL: (y - 6)(y - 4) = y(y) + y(-4) - 6(y) - 6(-4) = $y^{2}$ - 4y - 6y + 24 = $y^{2}$ - 10y + 24 2. Apply the zero factor property to the factored expression: a) y - 6 = 0 b) y - 4 = 0 3. Solve each linear equation: a) y = 6 b) y = 4 The solutions are {4, 6}.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.