## Intermediate Algebra (6th Edition)

1. Factor and check by multiplying with FOIL: (y - 6)(y - 4) = y(y) + y(-4) - 6(y) - 6(-4) = $y^{2}$ - 4y - 6y + 24 = $y^{2}$ - 10y + 24 2. Apply the zero factor property to the factored expression: a) y - 6 = 0 b) y - 4 = 0 3. Solve each linear equation: a) y = 6 b) y = 4 The solutions are {4, 6}.