## Intermediate Algebra (6th Edition)

Reorder the expression n(2n - 3) = 2 to 2$n^{2}$ - 3n - 2 = 0 1. Factor: 2$n^{2}$ - 3n - 2 = (2n + 1)(n - 2) 2. Apply the zero factor property to the factored expression: a) 2n + 1 = 0 b) n - 2 = 0 3. Solve each linear equation: a) n = -1/2 b) n = 2 The solutions are {-1/2, 2}.