Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.8 - Solving Equations by Factoring and Problem Solving - Exercise Set: 9

Answer

{1, 9}

Work Step by Step

Reorder $z^{2}$ + 9 = 10z to $z^{2}$ -10z + 9. 1. Factor: $z^{2}$ -10z + 9 = (z - 9)(z - 1) 2. Apply the zero factor property to the factored expression: a) z - 9 = 0 b) z - 1 = 0 3. Solve each linear equation: a) z = 9 b) z = 1 The solutions are {1, 9}.
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