Answer
$[17,\infty)$
Work Step by Step
The radicand of the given function, $
h(x)=\sqrt{x-17}-3
$ is a non-negative number. Hence,
\begin{array}{l}\require{cancel}
x-17\ge0
\\\\
x\ge17
.\end{array}
The domain is $
[17,\infty)
.$
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