Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Review - Page 632: 38

Answer

$(-7,-20),(2,\frac{5}{2})$

Work Step by Step

$x^{2}+2y=9$ Equation $(1)$ $5x-2y=5$ Equation $(2)$ Add Equation $(1)$ and Equation $(2)$ $x^{2}+2y+5x-2y=9+5$ $x^{2}+5x=14$ $x^{2}+5x-14=0$ By factoring, $(x+7)(x-2)=0$ $x=-7$ or $x=2$ Substitute $x$ values in Equation $(2)$ to get corresponding $y$ values. Let $x=-7$ $5x-2y=5$ $5(-7)-2y=5$ $-35-2y=5$ $-2y=5+35$ $-2y=40$ $y=-20$ Let $x=2$ $5x-2y=5$ $5(2)-2y=5$ $10-2y=5$ $-2y=5-10$ $-2y=-5$ $y=\frac{5}{2}$ $(-7,-20),(2,\frac{5}{2})$ satisfy the given equations.
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