Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Review - Page 632: 3

Answer

$\left( x+7 \right)^2+\left( y+9 \right)^2=11$

Work Step by Step

Using the standard form of the equation of circles which is given by $(x-h)^2+(y-k)^2=r^2$ where the center is $(h,k)$ and radius $r$, then the equation of the circle with the given center at $ (-7,-9) $ and the given radius is $ \sqrt{11} $ is \begin{array}{l} \left( x-(-7) \right)^2+\left( y-(-9) \right)^2=(\sqrt{11})^2\\\\ \left( x+7 \right)^2+\left( y+9 \right)^2=11 .\end{array}
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