Answer
No solution.
Work Step by Step
Rearrange the second equation to make $x=y+4$
Plug this value for $x$ into the first equation:
$(y+4)^2+y^2=4$
Expand and simplify:
$y^2+8y+16+y^2=4$
$2y^2+8y+16=4$
Divide both sides of the equation by 2:
$y^2+4y+8=2$
$y^2+4y+6=0$
Use the quadratic equation:
$\frac{-4±\sqrt{4^2-4(1)(6)}}{2(1)}$
$=\frac{-4±\sqrt{16-24}}{2}$
$=\frac{-4±\sqrt{-8}}{2}$
Since you cannot take the square root of a negative number, the result is imaginary and there is no solution.
