Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Appendix C - C - Exercise Set - Page 686: 9

Answer

(1,2)

Work Step by Step

We first write the equations in standard form, where the variables are isolated from the constants: 0x + 2y = 4 x + 2y = 5 We can then take the determinant of the variables from D= | 0 2| | 1 2| which would be 0*2 - 1*2 = -2 *Note: The determinant of a matrix |a b| |c d| can be calculated as a*d - b*c To get the determinant of the x side, our matrix is Dx = | 4 2| | 5 2| which would be 4*2 - 5*2 = -2 To get the determinant of the y side, our matrix is Dy = | 0 4| | 1 5| which would be 0*5 - 4*1 = -4 To get x, we take Dx/D = -2/-2 = 1 To get y, we take Dy/D = -4/-2 = 2. Therefore our ordered pair solution is (1,2)
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